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io.github.brkd-h1/empty-public-canary

Official registry Developer tools

Public-repo MCP canary with spoofed private repository.id for owned-account registry fallback test.

Source code Documentation

Install

Add this to your client's MCP configuration (Claude Desktop: claude_desktop_config.json; Cursor: .cursor/mcp.json; VS Code and others use the same "mcpServers" shape).

Remote (streamable-http)
Claude Code 
claude mcp add --transport http empty-public-canary 'https://bintool.brkd.no/anything/mcp-empty-public-canary'
JSON configuration (Claude Desktop, Cursor, VS Code) 
{
    "mcpServers": {
        "empty-public-canary": {
            "type": "http",
            "url": "https://bintool.brkd.no/anything/mcp-empty-public-canary"
        }
    }
}

Documentation

From the project's README on GitHub, refreshed weekly. Links open on GitHub.

mcp-empty-public

Minimal Model Context Protocol server used to validate registry publishing from this account.

Frequently asked questions

What is io.github.brkd-h1/empty-public-canary?

Public-repo MCP canary with spoofed private repository.id for owned-account registry fallback test.

How do I install io.github.brkd-h1/empty-public-canary?

It runs as a remote server. In Claude Code: claude mcp add --transport http empty-public-canary 'https://bintool.brkd.no/anything/mcp-empty-public-canary'. For other clients, paste the JSON configuration from this page into their MCP settings.

Does io.github.brkd-h1/empty-public-canary need an API key?

Its registry entry lists no required key or secret. Some features may still need an account with the service it connects to.

Is io.github.brkd-h1/empty-public-canary open source?

Its code is public on GitHub, but the repository does not declare a standard license.

Who maintains io.github.brkd-h1/empty-public-canary?

It is published by brkd-h1. AI.tn lists it but does not maintain or endorse it.

From the official MCP Registry. Listing is not an endorsement: review a server's code and permissions before giving it access to your data.